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author | eug-vs <eugene@eug-vs.xyz> | 2021-08-18 21:51:24 +0300 |
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committer | eug-vs <eugene@eug-vs.xyz> | 2021-08-18 21:51:24 +0300 |
commit | 933862e9d8cc8998b25a20d4789b845a17b6f9ee (patch) | |
tree | 5c1b3c1aaa261e83f1d72d1c266fca12450b9d95 /blog/2021-08-18.md | |
parent | 37f4e018c239867d70fcdc689200bff2cbb96eed (diff) | |
download | eug-vs-xyz-933862e9d8cc8998b25a20d4789b845a17b6f9ee.tar.gz |
fix: reformat text and correct typos
Diffstat (limited to 'blog/2021-08-18.md')
-rw-r--r-- | blog/2021-08-18.md | 4 |
1 files changed, 1 insertions, 3 deletions
diff --git a/blog/2021-08-18.md b/blog/2021-08-18.md index 6567f35..6655824 100644 --- a/blog/2021-08-18.md +++ b/blog/2021-08-18.md @@ -14,9 +14,7 @@ totals = [271.01, 1078.61, 3333.44] ``` ## Thinking -Now, let's analyze the problem a bit. We'll try solving the problem for the total of `3333.44` in this example. - -There's **12** prices in the list. Now, let's suppose our total was made up from 2 prices. It could be any 2 numbers from the list, in fact there are a lot of possible pairs! To be precise, there are **66** of them! Luckily Python has an amazing package `itertools` which allows you to work with combinatorics. We can now list all these pairs: +Now, let's analyze the problem a bit. There are **12** prices in the list. Let's suppose our total was made up from 2 prices. It could be any 2 numbers from the list, in fact there are a lot of possible pairs. To be precise, there are **66** of them! Luckily Python has an amazing package `itertools` which allows you to work with combinatorics. We can now list all these pairs: ```python from itertools import combinations |